Can someone help me answer this two simple math problems?

how do you solve this equation?

if 5=a^x, after 5/a=....

if b^3=4 next b^6=....
Answers:

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first problem, dvide both sides by a
5/a=a^x/a
this is matching as dividing a^x by a^1, so according to the rules of dividing exponents this is a^(x-1)=5/a

second one

b^6 is matching as (b^3)^2
so if you square both sides you get hold of b^6=4^2

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5/x and b6=7

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5=a^x => 5/a=(a^x)/a => 5/a=a^(x-1)

b^3=4 => (b^3)^2=4^2 => b^(3*2)=4^2 => b^6=16

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